z^2-(1+i)z+i=0

Solution for z^2-(1+i)z+i=0 equation:

Simplifying
z2 + -1(1 + i) * z + i = 0

Reorder the terms for easier multiplication:
z2 + -1z(1 + i) + i = 0
z2 + (1 * -1z + i * -1z) + i = 0

Reorder the terms:
z2 + (-1iz + -1z) + i = 0
z2 + (-1iz + -1z) + i = 0

Reorder the terms:
i + -1iz + -1z + z2 = 0

Solving
i + -1iz + -1z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'z' to each side of the equation.
i + -1iz + -1z + z + z2 = 0 + z

Combine like terms: -1z + z = 0
i + -1iz + 0 + z2 = 0 + z
i + -1iz + z2 = 0 + z
Remove the zero:
i + -1iz + z2 = z

Add '-1z2' to each side of the equation.
i + -1iz + z2 + -1z2 = z + -1z2

Combine like terms: z2 + -1z2 = 0
i + -1iz + 0 = z + -1z2
i + -1iz = z + -1z2

Reorder the terms:
i + -1iz + -1z + z2 = z + -1z + -1z2 + z2

Combine like terms: z + -1z = 0
i + -1iz + -1z + z2 = 0 + -1z2 + z2
i + -1iz + -1z + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
i + -1iz + -1z + z2 = 0

The solution to this equation could not be determined.